Last Stone Weight - Leetcode
We have a collection of stones, each stone has a positive integer weight. Each turn, we choose the two heaviest stones and smash them together. Suppose the stones have weights x and y with x <= y . The result of this smash is: If x == y , both stones are totally destroyed; If x != y , the stone of weight x is totally destroyed, and the stone of weight y has new weight y-x . At the end, there is at most 1 stone left. Return the weight of this stone (or 0 if there are no stones left.) Example 1: Input: [2,7,4,1,8,1] Output: 1 Explanation: We combine 7 and 8 to get 1 so the array converts to [2,4,1,1,1] then, we combine 2 and 4 to get 2 so the array converts to [2,1,1,1] then, we combine 2 and 1 to get 1 so the array converts to [1,1,1] then, we combine 1 and 1 to get 0 so the array converts to [1] then that's the value of last stone. Note: 1 <= stones.length <= 30 1 <= stones[i] <= 1000 class Solution { public int lastStoneWeight(