Get Maximum in Generated Array

 You are given an integer n. An array nums of length n + 1 is generated in the following way:

  • nums[0] = 0
  • nums[1] = 1
  • nums[2 * i] = nums[i] when 2 <= 2 * i <= n
  • nums[2 * i + 1] = nums[i] + nums[i + 1] when 2 <= 2 * i + 1 <= n

Return the maximum integer in the array nums​​​.

Example 1:

Input: n = 7
Output: 3
Explanation: According to the given rules:
  nums[0] = 0
  nums[1] = 1
  nums[(1 * 2) = 2] = nums[1] = 1
  nums[(1 * 2) + 1 = 3] = nums[1] + nums[2] = 1 + 1 = 2
  nums[(2 * 2) = 4] = nums[2] = 1
  nums[(2 * 2) + 1 = 5] = nums[2] + nums[3] = 1 + 2 = 3
  nums[(3 * 2) = 6] = nums[3] = 2
  nums[(3 * 2) + 1 = 7] = nums[3] + nums[4] = 2 + 1 = 3
Hence, nums = [0,1,1,2,1,3,2,3], and the maximum is 3.

Example 2:

Input: n = 2
Output: 1
Explanation: According to the given rules, the maximum between nums[0], nums[1], and nums[2] is 1.

Example 3:

Input: n = 3
Output: 2
Explanation: According to the given rules, the maximum between nums[0], nums[1], nums[2], and nums[3] is 2.

 

Constraints:

  • 0 <= n <= 100
Solution :

class Solution {
    public int getMaximumGenerated(int n) {
        if(n==0)
            return 0;
        else if(n==1)
            return 1;
        int nums[] = new int[n+1];
       
        nums[0] = 0;
        nums[1] = 1;
        
        int i, max =0;
        
        for(i=2;i<=n;i++){
            if(i % 2 == 0){
                nums [i] = nums[i/2];
            }
            else{
                nums[i] = nums[i/2] + nums[i/2+1];
            }
            max = Math.max(nums[i], max);
        }
        
        return max;
    }
}


Note:
Here, the problem itself clearly give you a solution. The solution for this problem can applied directly as explained in the problem [change only i value as explained in input 1]. But, if you follow this approach, there will be occurrence of error if n value is even[as explained in input 1, but n is even].

So, we need to approach the problem in different way.
1) Create a nums array with a size of n+1.
2) Initialize default values for nums[0] and nums[1].
3)For i>=2 till n,
 a)If i is even, then nums [i] = nums[i/2]
 b) If i is odd, then nums [i] = nums[i/2] + nums[i/2+1] (By using i/2, we can get values as represented in problem statement)
 c)For each nums[i], update max variable.
4) Finally return max.

Related Posts:


Like us? Please do share with your friends ..!!

Follow us to receive updates instantly.

If you have any feedback/suggestions, leave it in a comment section or contact us through our contact page which will be helpful for us to improve.

Comments

Popular posts from this blog

Balanced Binary Tree

First Unique Character in a String

Majority Element

Smallest Range II