Monk's Choice Of Numbers-Hackerearth
JAVA Solution
import java.util.*;
class TestClass {
public static void main(String args[] ) throws Exception {
Scanner s = new Scanner(System.in);
int t = s.nextInt();
while(t!=0)
{
ArrayList<Integer>hs = new ArrayList<Integer>();
int n = s.nextInt(), k = s.nextInt(), i, count=0;
int ar[] = new int[n];
for(i=0;i<n;i++)
{
ar[i] = s.nextInt();
String str = Integer.toBinaryString(ar[i]);
str = str.replaceAll("0","");
hs.add(str.length());
}
int len = hs.size();
Integer ak[] = new Integer[len];
hs.toArray(ak);
Arrays.sort(ak);
i=0;len--;
while(i<k)
{
count+=ak[len];
i++;
len--;
}
System.out.println(count);
t--;
}
}
}
Try this on Hackerearth
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