Special Matrix - Hackerearth

C++ 14 Solution

    #include<iostream>
    using namespace std;
    int main()
    {
         int t ;
         cin>>t;
            while(t!=0)
            {
                int n;
                cin>>n;
                int mid = n/2+1;
                char ar[n+1][n+1];
                int i, j, k, l;
                for(i=1;i<=n;i++)
                {
                    for(j=1;j<=n;j++)
                    {
                        cin>>ar[i][j];
                        if(ar[i][j]=='*')
                        {
                            k=i;
                            l=j;
                        }
                    }
                }
                cout<<abs(mid-k)+abs(mid-l)<<endl;
                t--;
            }
        return 0;
    } 

 

Click this link to try it on Hackerearth




The intention behind this blog is to help all my fellow programmers. Also to provide solutions for various coding platform problems with solution and explanation. I will add many tutorials in future. I am not a professional blogger but whenever time permits I will post. I hope you’ll enjoy the content and find it useful! Check out my Writer blog for a more valuable quotes. For any queries or suggestions, please feel free to reach out to me. Happy coding!

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