Who wants to be a Millionaire?-Hackerearth


C++14 Solution


#include <iostream>
#include <stdio.h>
using namespace std;
int main() {
 int test;
 cin >> test;
 while (test--) {
    int n;
    cin >> n;
    printf ("%.6f\n", (float)(n-1)*1.0/(float)(n));
 }
    return 0;
}

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The intention behind this blog is to help all my fellow programmers. Also to provide solutions for various coding platform problems with solution and explanation. I will add many tutorials in future. I am not a professional blogger but whenever time permits I will post. I hope you’ll enjoy the content and find it useful! Check out my Writer blog for a more valuable quotes. For any queries or suggestions, please feel free to reach out to me. Happy coding!

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