Maximum XOR of Two Numbers in an Array

 Given a non-empty array of numbers, a0, a1, a2, … , an-1, where 0 ≤ ai < 231.

Find the maximum result of ai XOR aj, where 0 ≤ i, j < n.

Example: 

Input: [3, 10, 5, 25, 2, 8]

Output: 28

Explanation: The maximum result is 5 ^ 25 = 28.


 

class Solution {

    public int findMaximumXOR(int[] nums) {

        int i, j, length = nums.length, max=0;

        for(i=0;i<length;i++){

            int tmp = 0;

            for(j=0;j<length;j++){

                if(i!=j){

                    tmp = nums[i]^nums[j];

                    if(tmp > max){

                        max = tmp;

                    }

                }

            }

        }

     return max;   

    }

}

The above solution is a Brute Force approach.

1) Take i, j for iteration.

2) For each i, do XOR operation with remaining all nums using j (inner loop).

3) Each XOR operation is stored in tmp variable.

4) If tmp is greater than max, then update max variable.

5) Finally return max.


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