Squares of a Sorted Array

Given an integer array nums sorted in non-decreasing order, return an array of the squares of each number sorted in non-decreasing order.

Example 1: 

Input: nums = [-4,-1,0,3,10]
Output: [0,1,9,16,100]
Explanation: After squaring, the array becomes [16,1,0,9,100].
After sorting, it becomes [0,1,9,16,100].

Example 2: 

Input: nums = [-7,-3,2,3,11]
Output: [4,9,9,49,121]

Constraints:

  • 1 <= nums.length <= 104
  • -104 <= nums[i] <= 104
  • nums is sorted in non-decreasing order.
Solution:

class Solution {
    public int[] sortedSquares(int[] nums) {
        
        for(int i=0;i<nums.length;i++){
            nums[i] = nums[i] * nums[i];
        }
        
        Arrays.sort(nums);
        
        return nums;
        
    }
}


Here, in this problem they mentioned that we need to return the output in a non-decreasing (i.e., increasing) order. We are going to solve the problem in most easiest and easily understandable solution.

1) Iterate the array and find a square of the each number and store it to same index position.
2) After complete iteration, sort the array and return the output.

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