Robot Bounded In Circle
On an infinite plane, a robot initially stands at (0, 0)
and faces north. The robot can receive one of three instructions:
"G"
: go straight 1 unit;"L"
: turn 90 degrees to the left;"R"
: turn 90 degress to the right.
The robot performs the instructions
given in order, and repeats them forever.
Return true
if and only if there exists a circle in the plane such that the robot never leaves the circle.
Example 1:
Input: "GGLLGG" Output: true Explanation: The robot moves from (0,0) to (0,2), turns 180 degrees, and then returns to (0,0). When repeating these instructions, the robot remains in the circle of
radius 2 centered at the origin.
Example 2:
Input: "GG" Output: false Explanation: The robot moves north indefinitely.
Example 3:
Input: "GL" Output: true Explanation: The robot moves from (0, 0) -> (0, 1) -> (-1, 1) -> (-1, 0) -> (0, 0) -> ...
Note:
1 <= instructions.length <= 100
instructions[i]
is in{'G', 'L', 'R'}
public boolean isRobotBounded(String ins) {
int x = 0, y = 0, length = ins.length(), i = 0, dir[][] = {{0, 1}, {1, 0}, {0, -1}, { -1, 0}};
for (int j = 0; j < length; ++j)
if (ins.charAt(j) == 'R')
i = (i + 1) % 4;
else if (ins.charAt(j) == 'L')
i = (i + 3) % 4;
else {
x += dir[i][0]; y += dir[i][1];
}
return x == 0 && y == 0 || i > 0;
}
}
Here let's take following assumptions,
A robot is starting at (0,0) and faces north (i.e.,) (0,1) and after one sequence of instructions,
1) If a robot returns to (0,0), then it forms a circle.
2) If robot finishes with face not towards north, it will get back to the initial status in another one or three sequences.
(x,y) is a location of robot
dir[][] - direction a robot is facing
i = (i+1)%4 -> robot turns right
i = (i+3)%4 -> robot turns left
3) Check final status after all instructions.
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