Search Insert Position

Given a sorted array and a target value, return the index if the target is found. If not, return the index where it would be if it were inserted in order.

You may assume no duplicates in the array.

Example 1:

Input: [1,3,5,6], 5
Output: 2

Example 2:

Input: [1,3,5,6], 2
Output: 1

Example 3:

Input: [1,3,5,6], 7
Output: 4

Example 4:

Input: [1,3,5,6], 0
Output: 0
 class Solution {
    public int searchInsert(int[] nums, int target) {
       
        int i = 0, length = nums.length;
       
        for(i=0;i<length;i++){
            if(nums[i] >= target){
                return i;
            }
            }
        return i;
    }
}


Here, we are iterating each element in arrays. While iterating to find perfect insert position, if current number is greater than or equal to target then that position will be result and no need to iterate further.

If no position are found and we are at end of array , then last position will be perfect for given target.


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The intention behind this blog is to help all my fellow programmers. Also to provide solutions for various coding platform problems with solution and explanation. I will add many tutorials in future. I am not a professional blogger but whenever time permits I will post. I hope you’ll enjoy the content and find it useful! Check out my Writer blog for a more valuable quotes. For any queries or suggestions, please feel free to reach out to me. Happy coding!

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