Group Anagrams
Given an array of strings, group anagrams together.
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Example:
class Solution {
public List<List<String>> groupAnagrams(String[] strs) {
if (strs.length == 0) return new ArrayList();
Map<String, List> ans = new HashMap<String, List>();
for (String s : strs) {
char[] ca = s.toCharArray();
Arrays.sort(ca);
String key = String.valueOf(ca);
if (!ans.containsKey(key)) ans.put(key, new ArrayList());
ans.get(key).add(s);
}
return new ArrayList(ans.values());
}
}
Here string is to be stored as a key to check whether the same string is already present or not. For comparison of string , it is to be converted to character array and sort it and compare it with other strings.
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Example:
Input: ["eat", "tea", "tan", "ate", "nat", "bat"]
,
Output:
[
["ate","eat","tea"],
["nat","tan"],
["bat"]
]
Note:- All inputs will be in lowercase.
- The order of your output does not matter.
class Solution {
public List<List<String>> groupAnagrams(String[] strs) {
if (strs.length == 0) return new ArrayList();
Map<String, List> ans = new HashMap<String, List>();
for (String s : strs) {
char[] ca = s.toCharArray();
Arrays.sort(ca);
String key = String.valueOf(ca);
if (!ans.containsKey(key)) ans.put(key, new ArrayList());
ans.get(key).add(s);
}
return new ArrayList(ans.values());
}
}
Here string is to be stored as a key to check whether the same string is already present or not. For comparison of string , it is to be converted to character array and sort it and compare it with other strings.
For more Leetcode Problems
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