Java If-Else

In this challenge, we test your knowledge of using if-else conditional statements to automate decision-making processes. An if-else statement has the following logical flow:

_{Source: Wikipedia}
Task
Given an integer,
, perform the following conditional actions:

• If

is odd, print Weird

If

is even and in the inclusive range of to

, print Not Weird

If

is even and in the inclusive range of to

, print Weird

If

is even and greater than

• , print Not Weird

Complete the stub code provided in your editor to print whether or not

is weird.

Input Format

A single line containing a positive integer,

.
Output Format

Print Weird if the number is weird; otherwise, print Not Weird.

Sample Input 0

3

Sample Output 0

Weird

Sample Input 1

24

Sample Output 1

Not Weird

Explanation

Sample Case 0:

is odd and odd numbers are weird, so we print Weird.
Sample Case 1:

and is even, so it isn't weird. Thus, we print Not Weird.

 import java.io.*;
import java.math.*;
import java.security.*;
import java.text.*;
import java.util.*;
import java.util.concurrent.*;
import java.util.regex.*;

public class Solution {
    private static final Scanner scanner = new Scanner(System.in);

    public static void main(String[] args) {
        int N = scanner.nextInt();
        scanner.skip("(\r\n|[\n\r\u2028\u2029\u0085])?");
        if(N%2==1)
            System.out.println("Weird\n");
        else{
            if(N>2&&N<5)
                System.out.println("Not Weird\n");
            else if(N>6&&N<=20)
                System.out.println("Weird\n");
            else
                System.out.println("Not Weird\n");
        }

        scanner.close();
    }
}